2[2(3-5)+4]=5[2(3-3x)+2]

Solution for 2[2(3-5)+4]=5[2(3-3x)+2] equation:

Simplifying
2[2(3 + -5) + 4] = 5[2(3 + -3x) + 2]

Combine like terms: 3 + -5 = -2
2[2(-2) + 4] = 5[2(3 + -3x) + 2]

Multiply 2 * -2
2[-4 + 4] = 5[2(3 + -3x) + 2]

Combine like terms: -4 + 4 = 0
2[0] = 5[2(3 + -3x) + 2]

Multiply 2 * 0
0 = 5[2(3 + -3x) + 2]

Anything times zero is zero.
0 = 5[2(3 + -3x) + 2]
0 = 5[(3 * 2 + -3x * 2) + 2]
0 = 5[(6 + -6x) + 2]

Reorder the terms:
0 = 5[6 + 2 + -6x]

Combine like terms: 6 + 2 = 8
0 = 5[8 + -6x]
0 = [8 * 5 + -6x * 5]
0 = [40 + -30x]

Solving
0 = 40 + -30x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '30x' to each side of the equation.
0 + 30x = 40 + -30x + 30x
Remove the zero:
30x = 40 + -30x + 30x

Combine like terms: -30x + 30x = 0
30x = 40 + 0
30x = 40

Divide each side by '30'.
x = 1.333333333

Simplifying
x = 1.333333333